I remembered this old problem solving technique from my 2nd year high school math teacher and found it quite amusing again. This is how he proved that 2 = 1!
Let a = b
Then a^2 = ab
Add a^2 to both sides of the equation,
Then a^2 + a^2 = a^2 + ab
Then 2a^2 = a^2 + ab
Subtract 2ab from both sides of the equation
Then 2a^2 -2ab = a^2+ ab - 2ab
Then 2a^2 -2ab = a^2 - ab
Factor out 2 from the left side of the equation
Then 2 (a^2-ab) = a^2-ab
Divide (a^2-ab) from both sides of the equation
Then 2 = 1!
Find the fallacy of this algebraic solution.
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